11th Class Chemistry Hydrocarbons / हाइड्रोकार्बन Question Bank 11th CBSE Chemistry Hydrocarbons

  • question_answer
    Complete the following reactions with appropriate structures of products? \[{{C}_{6}}{{H}_{5}}CH=C{{H}_{2}}\xrightarrow{B{{r}_{2}}}\]\[[A]\,\xrightarrow[\text{(ii)}\,\text{C}{{\text{H}}_{\text{3}}}\text{I}]{\text{(i)NaN}{{\text{H}}_{\text{2}}}\text{(3}\text{.0}\,\text{equiv}\text{.)}}B\]

    Answer:

       \[\underset{Styrene}{\mathop{{{C}_{6}}{{H}_{5}}CH=C{{H}_{2}}}}\,\xrightarrow{B{{r}_{2}}}\,\underset{\begin{smallmatrix}  \,\,\,\,\,\,\,\,\,\,\text{1,}\,\text{2-Dibromo-}\, \\  \text{1-phenylethane}\,\text{(A)} \end{smallmatrix}}{\mathop{{{C}_{6}}{{H}_{5}}-\underset{\begin{smallmatrix}  | \\  Br \end{smallmatrix}}{\mathop{C}}\,H-\underset{\begin{smallmatrix}  | \\  Br \end{smallmatrix}}{\mathop{C}}\,{{H}_{2}}}}\,\]\[\xrightarrow[(-2\,HBr)]{2\,NaN{{H}_{2}}}\,\underset{\text{Phenylacetylene}}{\mathop{{{C}_{6}}{{H}_{5}}-C\equiv CH}}\,\] Thus, [A] is 1, 2-dibromo 1-phenylethane and [B] is 1-phenylpropyne.


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