Answer:
\[AgCl\rightleftharpoons
\,A{{g}^{+}}\,+C{{l}^{-}}\]
In \[NaCl\] solution, \[[C{{l}^{-}}]\]
will increase. As \[[A{{g}^{+}}]\,[C{{l}^{-}}]\,={{K}_{sp}}\] remains constant,
\[[A{{g}^{+}}]\] will decrease, i.e., the solubility will be less in \[NaCl\]
solution than in water.
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