Answer:
Zinc lies below copper in the
electrochemical series and can therefore, release electrons to the \[C{{u}^{2+}}\]
ions. As a result, Zn is oxidised while \[C{{u}^{2+}}\] ions are reduced. Since
the concentration of \[C{{u}^{2+}}\] ions in the solution decreases, the blue colour
of the solution is slowly discharged.
\[Zn(s)+C{{u}^{2+}}(aq)\xrightarrow{\,}Z{{n}^{2+}}(aq)+Cu(s)\]
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