Answer:
Electronic configuration of \[_{16}S=1\,{{s}^{2}}\,2\,{{s}^{2}}\,2\,{{p}^{6}}\,3\,{{s}^{2}}\,3\,{{p}^{4}}\]
For \[1\,{{s}^{2}},\,n+l=1\,+0=1\] For \[2\,{{s}^{2}},\,n+l=2+0=2\] For \[2{{p}^{6}},\,n+l=2+1=3\]
For \[3\,{{s}^{2}},\,n+l=3+0=3\] For \[3{{p}^{4}},\,n+l=3+1=4\]
Thus, \[n+l=3\] for\[2{{p}^{6}}\] and \[3{{s}^{2}}\] electrons i.e., for 8 electrons.
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