Answer:
As
\[\text{1}\text{.66}\times
\text{1}{{0}^{-27}}\text{kg=}\left( \text{a}.\text{m}.\text{u} \right)\]
\[\therefore
\,\,\,\,\,\,1kg\,=\frac{1}{1.66\times {{10}^{-27}}}a.m.u.=0.6\times
{{10}^{27}}a.m.u.\]
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