11th Class Physics Motion in a Straight Line / सरल रेखा में गति Question Bank 11th CBSE Physics One Dimensional Motion

  • question_answer
    The distance travelled by a particle moving in a straight line is found to be proportional to the square of the time elapsed. Is it moving with constant speed or constant acceleration? Explain

    Answer:

                    Given, \[\text{x}\propto {{\text{t}}^{\text{2}}}\]or \[\text{x}=\text{k}{{\text{t}}^{\text{2}}}\]where k is a constant of proportionality. speed/velocity of the particle, \[v=\frac{dx}{dt}=\frac{d}{dt}(k{{t}^{2}})\]= 2kt ...(i) and acceleration of the particle, a = \[\frac{dv}{dt}=\frac{d}{dt}\] (2kt) = 2k ....(ii) From (i) and (it) we note that acceleration of the particle is constant whereas the velocity of the particle depends upon the time.


You need to login to perform this action.
You will be redirected in 3 sec spinner