Answer:
As
\[\overset{\to }{\mathop{\text{A}}}\,\,\,.\overset{\to }{\mathop{\text{B}}}\,\]
; so\[\overset{\to }{\mathop{\text{A}}}\,\] is perpendicular to \[\overset{\to
}{\mathop{\text{B}}}\,\].
As
\[\overset{\to }{\mathop{\text{A}}}\,\,\,.\overset{\to }{\mathop{\text{C}}}\,\];
so\[\overset{\to }{\mathop{\text{A}}}\,\] is perpendicular to \[\overset{\to
}{\mathop{\text{C}}}\,\]
As
\[\overset{\to }{\mathop{\text{B}}}\,\times \overset{\to
}{\mathop{\text{C}}}\,\]is is perpendicular to both \[\overset{\to
}{\mathop{\text{B}}}\,\] and \[\overset{\to }{\mathop{\text{C}}}\,\], so \[\overset{\to }{\mathop{\text{B}}}\,\times \overset{\to
}{\mathop{\text{C}}}\,\]is parallel to \[\overset{\to }{\mathop{A}}\,\].
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