question_answer

Write down the relation between vectors \[\vec{A}\]and \[\vec{B}\]in each case.

Answer:

                The angle which the given velocity makes with the north direction is\[\text{18}0{}^\circ -\text{3}0{}^\circ =\text{15}0{}^\circ \]. The component velocity along north \[=\text{v cos15}0{}^\circ =\text{1}00\times (-\sqrt{3}/\text{2})=-\text{86}.\text{6 km}{{\text{h}}^{-\text{1}}}\]. The angle which the given velocity makes with the east direction is\[\text{9}0{}^\circ +\text{3}0{}^\circ =\text{12}0{}^\circ \], The component velocity along east \[=\text{vcos 12}0{}^\circ =\text{1}00\times \left( -\text{1}/\text{2} \right)=-\text{5}0\text{ km}{{\text{h}}^{-\text{1}}}\].