question_answer

Two bodies are projected at angle Q and \[\left( {{90}^{o}}-\theta  \right)\] to the horizontal with the same speed. Find the ratio of their time of flight.                

Answer:

\[{{T}_{1}}=2u\sin \theta /g\]and \[{{T}_{2}}=2u\sin \left( {{90}^{o}}-\theta  \right)\]                      so \[{{T}_{1}}/{{T}_{2}}=\sin \theta /\cos \theta =\tan \theta \].