Answer:
The reaction is known as \[\beta \]-elimination
and the major product is pent-2-ene according to Saytzeff's rule.
\[\underset{\text{2-Bromopentane}}{\mathop{\overset{\beta
}{\mathop{C}}\,{{H}_{3}}-\underset{\begin{smallmatrix}
| \\
Br
\end{smallmatrix}}{\mathop{C}}\,H-\overset{\beta
}{\mathop{C}}\,{{H}_{2}}-C{{H}_{2}}-C{{H}_{3}}}}\,\xrightarrow{\text{KOH}\,\text{(alc)}}\]\[\underset{\text{Pent-2-ene}}{\mathop{C{{H}_{3}}-CH=CH-C{{H}_{2}}-C{{H}_{3}}+KBr+{{H}_{2}}O}}\,\]
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