Answer:
(a)\[C{{H}_{2}}=CHCl\] (b) \[C{{F}_{2}}=C{{F}_{2}}\] (c) \[C{{H}_{2}}=\overset{\begin{smallmatrix} COOC{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}\].
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