Answer:
The configuration of copper in the
two oxidation states is:
\[Cu(I)\, &
:\,\,\,[Ar]{{\,}^{18}}\,3{{d}^{10}};\,\,Cu(II)\,:\,\,{{[Ar]}^{18}}\,3{{d}^{9}}\].
Cu (I) has all filled orbitals and is diamagnetic
in nature. On the other hand, Cu (II) has one half-filled orbital and is paramagnetic
in nature.
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