Answer:
Iodide ion \[({{I}^{-}})\] is a
strong reducing agent and reduces \[F{{e}^{3+}}\] ion to \[F{{e}^{2+}}\] ion.
Therefore, ferric iodide \[(Fe{{I}_{3}})\] does not exist while ferrous iodide \[(Fe{{I}_{2}})\]does
exist. On the other hand, chloride ion \[(C{{l}^{-}})\] being a weak reducing
agent cannot reduce \[F{{e}^{3+}}\] ion. As a result, ferric chloride \[(FeC{{l}_{3}})\]is
quite stable.
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