question_answer

             \[S{{F}_{6}}\] is not easily hydrolysed whereas \[S{{F}_{4}}\] is easily hydrolysed. Assign reason.

Answer:

                In \[S{{F}_{4}},\] the sulphur atom has +4 oxidation state and can extend the same to +6 by accepting electron pairs from \[{{H}_{2}}O\]molecules. Therefore, it can be hydrolysed. But in \[S{{F}_{6}}\], the oxidation state of sulphur is already +6 and cannot increase the same any more. Therefore, it cannot be easily hydrolysed. For chemical reaction, consult section 7.15 (Chemical properties of oxygen family).