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10th Class Mathematics Related to Competitive Exam Question Bank Algebra

  • question_answer
    The solution of \[\frac{2x+3}{2x-1}=\frac{3x-1}{3x+1}\]is

    A) \[\frac{1}{8}\]                   

    B)        \[-\frac{1}{8}\]  

    C) \[\frac{8}{3}\]                   

    D)        \[-\frac{8}{3}\]

    Correct Answer: B

    Solution :

    Given    \[\frac{2x+3}{2x-1}=\frac{3x-1}{3x+1}\] By dividend        \[\frac{2x+3}{(2x+3)-(2x-1)}\]                 \[=\frac{3x-1}{(3x-1)-(3x+1)}\] or            \[\frac{2x+3}{4}=\frac{3x-1}{-2}\] or            \[2x+3=-6x+2\] or            \[8x=-1\] \[\therefore \]    \[x=-\frac{1}{8}\]


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