10th Class Mathematics Related to Competitive Exam Question Bank Algebra

  • question_answer
    The value of \[{{x}^{2}}-6x+13\]can never be less than

    A) 4                                               

    B) 5

    C) 4.5                         

    D)        7

    Correct Answer: A

    Solution :

    \[\because \]     \[{{x}^{2}}-6x+13={{x}^{2}}-6x+9+4\]                                       \[={{(x-3)}^{2}}+4\]                                       \[>4\] because \[{{(x-3)}^{2}}\] can never be less than zero least value of\[{{x}^{2}}-6x+13=4\]


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