A) \[pq+qr-2{{q}^{2}}=0\]
B) \[pq+qr-2{{p}^{2}}=0\]
C) \[pq+qr-pqr=0\]
D) \[pq+qr-2{{r}^{2}}=0\]
Correct Answer: A
Solution :
If \[p,\,\,q\] and \[r\] are in\[A.\text{ }P.\], then \[p+r=2q\] \[\Rightarrow \] \[p+r-2q=0\]multiply by\[q\] \[\therefore \] \[pq+qr-2{{q}^{2}}=0\]
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