A) \[\frac{{{p}^{2}}-{{q}^{2}}}{2}\]
B) \[\frac{{{q}^{2}}-{{p}^{2}}}{2q}\]
C) \[\frac{{{q}^{2}}-{{p}^{2}}}{2}\]
D) \[\frac{{{p}^{2}}-{{q}^{2}}}{2q}\]
Correct Answer: B
Solution :
\[{{x}^{2}}+{{p}^{2}}={{q}^{2}}-2qx+{{x}^{2}}\] or \[{{x}^{2}}+2qx-{{x}^{2}}={{q}^{2}}-{{p}^{2}}\] or \[2qx={{q}^{2}}-{{p}^{2}}\] or \[x=\frac{{{q}^{2}}-{{p}^{2}}}{2q}\]
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