question_answer

The sum of the roots of \[\frac{1}{x+a}+\frac{1}{x+b}=\frac{1}{c}\]is zero. The product of the roots is

A)  \[-\frac{1}{2}({{a}^{2}}+{{b}^{2}})\]        

B)         0

C)  \[\frac{1}{2}(a+b)\]         

D)         \[2({{a}^{2}}+{{b}^{2}})\]