A) 11
B) 13
C) 17
D) 19
Correct Answer: C
Solution :
\[{{2}^{16}}-1={{({{2}^{4}})}^{4}}-1\] \[={{(16)}^{4}}-1\] \[=(16-1)(16+1)({{16}^{2}}+1)\] Hence, \[{{2}^{16}}-1\] is divisible by\[17\].
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