A) \[\frac{{{b}^{n+1}}-{{a}^{n+1}}}{{{a}^{n-1}}.b}\]
B) \[\frac{{{a}^{n}}-{{b}^{n}}}{ab}\]
C) \[\frac{{{a}^{n}}-{{b}^{n}}}{{{a}^{n}}{{b}^{n}}}\]
D) \[\frac{{{a}^{n+1}}-{{b}^{n+1}}}{a{{b}^{n}}}\]
Correct Answer: A
Solution :
Remainder obtained \[=\left[ {{\left( \frac{b}{a} \right)}^{n}}-\frac{a}{b} \right]=\left[ \frac{{{b}^{n}}}{{{a}^{n}}}-\frac{a}{b} \right]=\frac{{{b}^{n+1}}-{{a}^{n+1}}}{{{a}^{n-1}}\cdot b}\]
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