A) \[(2x+3y)(10x+3y)\]
B) \[-(2x+3y)(10x+3y)\]
C) \[(2x+10y)(x+3y)\]
D) \[-(2x+10y)(x+3y)\]
Correct Answer: B
Solution :
\[16{{x}^{2}}-9{{(y+2x)}^{2}}={{(4x)}^{2}}-{{[3(y+2x)]}^{2}}\] \[=[4x+3(y+2x)][4x-3)(y+2x)]\] \[=(10x+3y)(-2x+3y)\] \[=-(2x+3y)(10+3y)\]
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