A) ±2
B) ± 1
C) ± 3
D) ± 4
Correct Answer: B
Solution :
Let the roots are \[\alpha ,\,\,\alpha ,\,\,\beta \] therefore \[2\alpha +\beta =0\] or \[\beta =-2\alpha \] and \[{{\alpha }^{2}}\beta =-q\] \[\Rightarrow \] \[-2{{\alpha }^{3}}=-q\] or \[{{a}^{3}}=\frac{q}{2}\] ? (i) Also\[{{\alpha }^{2}}+\alpha \beta +\alpha \beta =-3\] or \[-3{{\alpha }^{2}}=-3\] or \[{{\alpha }^{2}}=1\] \[\therefore \] \[\alpha =\pm 1\] Substituting the value of a in equation (i), we get \[\pm 1=\frac{q}{2}\] or \[q=\pm 2\]
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