question_answer

Find the side of a square field of area \[\frac{9}{16}{{x}^{2}}+\frac{25}{36}{{y}^{2}}-\frac{5}{4}xy\,\,sq.\]units.

A)  \[\left( \frac{3}{4}x+\frac{5}{6}y \right)\] units

B)  \[\left( \frac{3}{5}x-\frac{5}{6}y \right)\] units

C)  \[\left( \frac{3}{5}x+\frac{5}{6}y \right)\]units

D)  \[\left( \frac{3}{4}x-\frac{5}{6}y \right)\]units