A) \[\frac{bC-a}{C-1}\]
B) \[\frac{C-a}{C-b}\]
C) \[\frac{C+a}{C+b}\]
D) \[\frac{1-C}{a-bC}\]
Correct Answer: A
Solution :
\[C=\frac{x-a}{x-b}\] \[\Rightarrow \] \[C(x-b)=x-a\]\[\Rightarrow \] \[x=\frac{bC-a}{C-1}\]
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