A) \[C{{l}_{2}}\] and \[{{H}_{2}}\]
B) \[C{{l}_{2}}\] and \[Na-Hg\]
C) \[C{{l}_{2}}\] and \[Na\]
D) \[C{{l}_{2}}\] and \[{{O}_{2}}\]
Correct Answer: A
Solution :
\[2NaCl+2{{H}_{2}}O\to 2NaOH+{{H}_{2}}+C{{l}_{2}}\]
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