A) Oxidation with atmospheric oxygen
B) Combination with atmospheric \[C{{O}_{2}}\]
C) Dehydration
D) Hydration to yield another hydrate
Correct Answer: D
Solution :
Setting of plaster of paris is exothermic process \[CaS{{O}_{4}}.\frac{1}{2}{{H}_{2}}O\xrightarrow{{{H}_{2}}O}\underset{\text{Orthorhombic }}{\mathop{CaS{{O}_{4}}.2{{H}_{2}}O}}\,\]\[\xrightarrow{\text{Hardening}}\underset{\begin{smallmatrix} \text{Mono orthorhombic } \\ \text{Gypsum} \end{smallmatrix}}{\mathop{CaS{{O}_{4}}.2{{H}_{2}}O}}\,\] The setting is due to formation of another hydrate
You need to login to perform this action.
You will be redirected in
3 sec
