A) \[Be{{(OH)}_{2}}\]
B) \[Mg{{(OH)}_{2}}\]
C) \[Ca{{(OH)}_{2}}\]
D) \[Ba{{(OH)}_{2}}\]
Correct Answer: D
Solution :
\[Be{{(OH)}_{2}}<Mg{{(OH)}_{2}}<Ca{{(OH)}_{2}}\]\[<Sr{{(OH)}_{2}}<Ba{{(OH)}_{2}}\] On moving down the group basic character increases.
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