A) Silicon carbide
B) Calcium carbide
C) Aluminium carbide
D) Iron carbide
Correct Answer: C
Solution :
\[\underset{\begin{smallmatrix} \text{Aluminium } \\ \text{carbide} \end{smallmatrix}}{\mathop{A{{l}_{4}}{{C}_{3}}}}\,+\,\,\,6{{H}_{2}}O\to \underset{\text{Methane}}{\mathop{3C{{H}_{4}}}}\,+2A{{l}_{2}}{{O}_{3}}\]
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