A) \[C{{H}_{3}}C{{H}_{2}}OH\]
B) \[C{{H}_{3}}CHO\]
C) \[C{{H}_{3}}COC{{H}_{3}}\]
D) \[C{{H}_{3}}C{{O}_{2}}C{{H}_{2}}\]
Correct Answer: A
Solution :
Compounds having active hydrogen \[\left( ROH,{{H}_{2}}O,R-N{{H}_{2}} \right)\] can form alkane when treated with Grignard?s reagent \[C{{H}_{3}}C{{H}_{2}}OH+C{{H}_{3}}MgBr\to C{{H}_{4}}\]\[+Mg<\begin{matrix} Br\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\ OC{{H}_{2}}C{{H}_{3}} \\ \end{matrix}\]
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