A) Sodium acetate is heated with sodalime
B) Iodomethane is reduced
C) Aluminium carbide reacts with water
D) All of these
Correct Answer: D
Solution :
\[\underset{\text{Sod}\text{.}\,\text{acetate}}{\mathop{C{{H}_{3}}COONa}}\,+NaOH\xrightarrow{CaO}C{{H}_{4}}+N{{a}_{2}}C{{O}_{3}}\] \[\underset{\text{Iodomethane}}{\mathop{C{{H}_{3}}I}}\,+2H\xrightarrow[\operatorname{Re}duction]{}C{{H}_{4}}+HI\] \[\underset{\text{Aluminium}\,\text{carbide}}{\mathop{A{{l}_{4}}{{C}_{3}}+6{{H}_{2}}O}}\,\to 3C{{H}_{4}}+2A{{l}_{2}}{{O}_{3}}\]
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