A) \[C{{H}_{3}}.CHBr.CHBr.C{{H}_{3}}\]
B) \[C{{H}_{2}}Br.C{{H}_{2}}Br\]
C) \[CHBr=CHBr\]
D) \[C{{H}_{3}}CHB{{r}_{2}}\]
Correct Answer: D
Solution :
In gemdihalide both the halogen atoms are present on the same carbon atom while in vicdihalide both the halogen atoms are present on adjacent carbon atoms. \[\underset{\text{Gemdihalide}}{\mathop{C{{H}_{3}}-CHB{{r}_{2}}}}\,\] \[\underset{vic\text{-}\text{dihalide}}{\mathop{\underset{\underset{Br\,\,\,}{\mathop{|\,\,\,\,\,\,\,}}\,}{\mathop{C{{H}_{2}}}}\,-\underset{\underset{Br\,\,\,\,}{\mathop{|\,\,\,\,\,\,\,\,}}\,}{\mathop{C{{H}_{2}}}}\,}}\,\]
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