A) 1-bromo-2-methylbutane
B) 2-bromo-2-methylbutane
C) 2-bromo-3-methylbutane
D) 1-bromo-3-methylbutane
Correct Answer: B
Solution :
\[{{H}_{3}}C-\underset{C{{H}_{3}}\,\,}{\mathop{\underset{|\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{CH-}}\,}}\,C{{H}_{2}}-C{{H}_{3}}+B{{r}_{2}}\xrightarrow{{}}\] \[\underset{\text{Major}}{\mathop{\begin{matrix} \,\,\,\,Br \\ | \\ {{H}_{3}}C-C-C{{H}_{2}} \\ | \\ \,\,\,\,\,\,C{{H}_{3}} \\ \end{matrix}-C{{H}_{3}}}}\,\]
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