A) 1-Butene
B) 1-Butyne
C) 2-Butene
D) All of these
Correct Answer: C
Solution :
\[C{{H}_{3}}-\underset{\underset{H\,\,\,}{\mathop{|\,\,\,\,\,}}\,}{\mathop{CH}}\,-\underset{\underset{Cl\,\,}{\mathop{|\,\,\,\,}}\,}{\mathop{CH}}\,-\underset{\underset{H\,\,\,\,\,}{\mathop{|\,\,\,\,\,\,\,\,}}\,}{\mathop{C{{H}_{2}}}}\,\underset{-\,HCl}{\mathop{\xrightarrow{alc.\,NaOH}}}\,\]\[C{{H}_{3}}CH=CH-C{{H}_{3}}\]
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