A) \[BrC{{H}_{2}}-C{{H}_{2}}Br\]
B) \[ClC{{H}_{2}}-C{{H}_{2}}Br\]
C) Both A and B
D) None of these
Correct Answer: C
Solution :
\[C{{H}_{2}}=C{{H}_{2}}\,+B{{r}_{2}}\xrightarrow{NaCl}\underset{\text{1,2}-\text{dibromo}\,\text{ethane}}{\mathop{\underset{\underset{Br\,\,\,}{\mathop{|\,\,\,\,\,\,\,}}\,}{\mathop{C{{H}_{2}}}}\,-\underset{\underset{Br\,\,\,}{\mathop{|\,\,\,\,\,\,\,\,}}\,}{\mathop{C{{H}_{2}}}}\,}}\,\]\[\underset{\text{1}-\text{bromo}-\text{2}-\text{chloro}\,\text{ethane}}{\mathop{+\underset{\underset{Cl\,\,\,}{\mathop{\,\,|\,\,\,\,\,\,\,\,\,}}\,}{\overset{2\,\,\,\,\,\,}{\mathop{C{{H}_{2}}}}}\,-\underset{\underset{Br\,\,}{\mathop{|\,\,\,\,\,\,}}\,}{\overset{1\,\,\,\,\,\,\,}{\mathop{C{{H}_{2}}}}}\,}}\,\]
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