A) \[C{{H}_{2}}=C{{H}_{2}}\]
B) \[C{{H}_{3}}-CH=C{{H}_{2}}\]
C) \[{{(C{{H}_{3}})}_{2}}C=C{{(C{{H}_{3}})}_{2}}\]
D) \[C{{H}_{3}}-CH=CH-C{{H}_{3}}\]
Correct Answer: C
Solution :
\[C{{H}_{3}}\underset{\,\,C{{H}_{3}}}{\mathop{\underset{|\,\,\,\,\,}{\mathop{-\,C=}}\,\,}}\,\underset{C{{H}_{3}}\,\,\,\,\,\,}{\mathop{\underset{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{C-C{{H}_{3}}}}\,}}\,\]\[\underset{(2)\,Zn/{{H}_{2}}O}{\mathop{\xrightarrow{(1)\,{{O}_{3}}\,\,\,\,\,\,\,\,}}}\,\] \[\underset{\text{Acetone}}{\mathop{C{{H}_{3}}-\underset{\underset{\,\,C{{H}_{3}}}{\mathop{|\,\,\,\,\,\,}}\,}{\mathop{CO}}\,+\underset{\underset{\,\,\,C{{H}_{3}}}{\mathop{|\,\,\,\,\,}}\,}{\mathop{OC}}\,-C{{H}_{3}}}}\,\]
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