A) Formaldehyde
B) Ethyl alcohol
C) Ozonide
D) Acetaldehyde
Correct Answer: A
Solution :
\[C{{H}_{2}}=C{{H}_{2}}\underset{2\,)\,Zn/{{H}_{2}}O}{\mathop{\xrightarrow{1\,)\,{{O}_{3}}}}}\,\underset{\text{Formaldehyde}}{\mathop{HCHO+HCHO}}\,\]
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