A) n-propyl alcohol
B) Isopropyl alcohol
C) Ethyl alcohol
D) Butyl alcohol
Correct Answer: B
Solution :
\[\underset{\text{Propylene}}{\mathop{C{{H}_{2}}=CH-C{{H}_{3}}+{{H}_{2}}O}}\,\xrightarrow{{{H}_{2}}S{{o}_{4}}}\]\[\underset{\text{Isopropyl alcohol}}{\mathop{C{{H}_{3}}-\overset{OH}{\mathop{\overset{|}{\mathop{C}}\,H}}\,-C{{H}_{3}}}}\,\] Thus in this reaction isopropyl alcohol is formed.
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