A) \[s{{p}^{2}}-sp\]
B) \[s{{p}^{3}}-s{{p}^{3}}\]
C) \[s{{p}^{2}}-s{{p}^{2}}\]
D) \[s{{p}^{3}}-sp\]
Correct Answer: A
Solution :
\[HC\equiv \overset{sp}{\mathop{C}}\,-\overset{s{{p}^{2}}}{\mathop{CH}}\,=C{{H}_{2}}\]
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