A) Tetrahedral, planar and linear
B) Tetrahedral, linear and planar
C) Pyramidal, planar and linear
D) Tetrahedral, pyramidal and planar
Correct Answer: D
Solution :
\[CH\equiv CH\xrightarrow{NaN{{H}_{2}}}CH\equiv {{C}^{-}}N{{a}^{+}}\underset{-NaI}{\mathop{\xrightarrow{C{{H}_{3}}I}}}\,CH\equiv C-C{{H}_{3}}\] \[\underset{\text{Pent}-\text{2}-\text{yne}}{\mathop{{{C}_{2}}{{H}_{5}}-C\equiv C-C{{H}_{3}}}}\,\underset{-NaI}{\mathop{\xleftarrow{{{C}_{2}}{{H}_{5}}I}}}\,N{{a}^{+}}\,{{C}^{-}}\equiv C-C{{H}_{3}}\]
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