A) \[{{C}_{2}}{{H}_{2}}\]
B) \[{{C}_{2}}{{H}_{4}}\]
C) \[{{C}_{2}}{{H}_{6}}\]
D) \[C{{H}_{4}}\]
Correct Answer: A
Solution :
\[CH\equiv CH+2B{{r}_{2}}\xrightarrow{CC{{l}_{4}}}\underset{\underset{Br\,}{\mathop{|\,\,\,\,}}\,}{\overset{\overset{Br}{\mathop{|\,\,\,\,}}\,}{\mathop{CH}}}\,-\underset{\underset{Br\,}{\mathop{|\,\,\,\,}}\,}{\overset{\overset{Br\,}{\mathop{|\,\,\,\,}}\,}{\mathop{CH}}}\,\] \[CH\equiv CH+N{{H}_{4}}OH+AgN{{O}_{3}}\to \underset{\begin{smallmatrix} \text{Di-silver}\,\text{acetylide} \\ \,\,\,\,\,\,\,\text{white}\,\text{ppt}\text{.} \end{smallmatrix}}{\mathop{Ag-C\equiv C-Ag}}\,\]
You need to login to perform this action.
You will be redirected in
3 sec
