A) Anhydrous \[AlC{{l}_{3}}\]
B) \[HgS{{O}_{4}}\]
C) Pd
D) Pt
Correct Answer: B
Solution :
\[CH\equiv CH+{{H}_{2}}O\underset{1%\,HgS{{O}_{4}}}{\mathop{\xrightarrow{40%\,{{H}_{2}}S{{O}_{4}}}}}\,\]\[C{{H}_{2}}\underset{C{{H}_{3}}CHO}{\mathop{\underset{\downarrow \,\,\,\,\,\,\,\,}{\mathop{=CHOH}}\,\,\,\,\,\,\,\,\,}}\,\]
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