A) \[{{\tan }^{-1}}\frac{3}{4},{{\tan }^{-1}}\left( -\frac{3}{4} \right)\]
B) \[{{\tan }^{-1}}\frac{1}{3},{{\tan }^{-1}}\left( -\frac{1}{3} \right)\]
C) \[{{\tan }^{-1}}\frac{4}{3},{{\tan }^{-1}}\left( -\frac{4}{3} \right)\]
D) \[{{\tan }^{-1}}\frac{1}{2},{{\tan }^{-1}}\left( -\frac{1}{2} \right)\]
Correct Answer: C
Solution :
\[\tan \theta =\pm 2\frac{\sqrt{{{h}^{2}}-ab}}{a+b}=\pm 2\frac{\sqrt{144-44}}{15}=\pm \frac{4}{3}\]. \[\Rightarrow \theta ={{\tan }^{-1}}\left( \pm \frac{4}{3} \right)\] .
You need to login to perform this action.
You will be redirected in
3 sec
