question_answer

Angle between \[x=2\] and \[x-3y=6\] is                      [MNR 1988]

A)            \[\infty \]                                    

B)            \[{{\tan }^{-1}}(3)\]

C)            \[{{\tan }^{-1}}\left( \frac{1}{3} \right)\]                               

D) None of these

Correct Answer: B

Solution :

           \[\theta ={{90}^{o}}-{{\tan }^{-1}}\left( \frac{1}{3} \right)\]                    \[\tan \theta =\cot \left[ {{\tan }^{-1}}\left( \frac{1}{3} \right) \right]=3\]                    \[\Rightarrow \theta ={{\tan }^{-1}}(3)\].