A) \[\frac{3x+4y-7}{\sqrt{25}}=\pm \frac{12x+5y+17}{\sqrt{169}}\]
B) \[\frac{3x+4y+7}{\sqrt{25}}=\frac{12x+5y+17}{\sqrt{169}}\]
C) \[\frac{3x+4y+7}{\sqrt{25}}=\pm \frac{12x+5y+17}{\sqrt{169}}\]
D) None of these
Correct Answer: A
Solution :
By direct formulae \[\frac{{{a}_{1}}x+{{b}_{1}}y+{{c}_{1}}}{\sqrt{a_{1}^{2}+b_{1}^{2}}}=\pm \frac{{{a}_{2}}x+{{b}_{2}}y+{{c}_{2}}}{\sqrt{a_{2}^{2}+b_{2}^{2}}}\] \[\frac{3x+4y-7}{\sqrt{{{3}^{2}}+{{4}^{2}}}}=\pm \frac{12x+5y+17}{\sqrt{{{(12)}^{2}}+{{(5)}^{2}}}}\] \[\frac{3x+4y-7}{5}=\pm \frac{12x+5y+17}{13}\].
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