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JEE Main & Advanced Mathematics Straight Line Question Bank Angle between two straight lines, Bisector of angle between two lines

  • question_answer
    The bisector of the acute angle formed between the lines \[4x-3y+7=0\]and \[3x-4y+14=0\]has the equation  [Pb. CET 2004]

    A)            \[x+y+3=0\]                           

    B)            \[x-y-3=0\]

    C)            \[x-y+3=0\]                             

    D)            \[3x+y-7=0\]

    Correct Answer: C

    Solution :

    The equation of bisector of acute angle formed between the lines \[4x-3y+7=0\] and \[3x-4y+14=0\] is \[\frac{4x-3y+7}{\sqrt{16+9}}=-\frac{3x-4y+14}{\sqrt{16+9}}\] Þ\[7x-7y+21=0\] Þ \[x-y+3=0\].


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