A) 1 : 2
B) 2 : 1
C) 1 : 3
D) 3 : 1
Correct Answer: B
Solution :
Given that \[{{9}^{th}}\] term \[=a+(9-1)d=0\]\[\Rightarrow a+8d=0\] Now ratio of \[{{29}^{th}}\] and \[{{19}^{th}}\] terms \[=\frac{a+28d}{a+18d}=\frac{(a+8d)+20d}{(a+8d)+10d}=\frac{20d}{10d}=\frac{2}{1}\].
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