JEE Main & Advanced Mathematics Sequence & Series Question Bank Arithmetic Progression

  • question_answer
    The sum of 24 terms of the following series \[\sqrt{2}+\sqrt{8}+\sqrt{18}+\sqrt{32}+.........\] is

    A) 300

    B) \[300\sqrt{2}\]

    C) \[200\sqrt{2}\]

    D) None of these

    Correct Answer: B

    Solution :

    We have \[\sqrt{2}+\sqrt{8}+\sqrt{18}+\sqrt{32}+......\] \[=1\sqrt{2}+2\sqrt{2}+3\sqrt{2}+4\sqrt{2}+........\] = \[\sqrt{2}[1+2+3+4+..........\text{upto}\ 24\ \text{terms}]\] \[=\sqrt{2}\times \frac{24\times 25}{2}=300\sqrt{2}\].


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