A) \[-\frac{5}{6}\]
B) \[-\frac{1}{2}\]
C) 1
D) \[-\frac{3}{2}\]
Correct Answer: D
Solution :
Given series \[\frac{1}{2}+\frac{1}{3}+\frac{1}{6}+........\] Here\[a=\frac{1}{2}\], common difference \[d=-\frac{1}{6}\] and \[n=9\]. \[\Rightarrow \] \[{{S}_{9}}=\frac{9}{2}\left[ 2\times \frac{1}{2}+(9-1)\left( -\frac{1}{6} \right) \right]=-\frac{3}{2}\].
You need to login to perform this action.
You will be redirected in
3 sec
