A) 5
B) 7
C) 9
D) 11
Correct Answer: B
Solution :
Let four numbers are\[a-3d,\,a-d,\ a+d,\ a+3d\]. Now \[\frac{b}{a}=\frac{d}{c}\]\[\Rightarrow \]\[a=4\] and\[(a-d)(a+d)=15\]\[\Rightarrow \]\[{{a}^{2}}-{{d}^{2}}=15\]\[\Rightarrow \]\[d=1\] Thus required numbers are 1, 3, 5, 7. Hence greatest number is 7.
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